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Moments Questions in Combined Science Physics: Step-by-Step

30 July 2026 · Dojo Education · 4 min read

Moments Questions in Combined Science Physics: Step-by-Step

Moments questions are some of the most predictable marks in the O-Level Combined Science Physics paper. Almost every year there is a balanced beam, a seesaw, a spanner or a crane, and almost every year students lose marks not because the physics is hard, but because they measure the wrong distance or forget to state equilibrium. Here is the exact method our tutors used when we sat these papers, plus the phrasing markers want to see.

What the syllabus actually asks for

For Combined Science Physics you need to be able to:

Two definitions must be word-perfect in your head:

Moment of a force = force × perpendicular distance from the pivot. Unit: newton metre (N m).

Principle of moments: when a body is in equilibrium, the sum of the clockwise moments about any pivot equals the sum of the anticlockwise moments about that pivot.

Notice the word "perpendicular". That single word is where a lot of marks disappear.

The five-step method

Use the same five steps every single time, even for a question that looks easy. Consistency is what stops careless errors under time pressure.

  1. Draw and label every force. Arrows for each weight, each pull, and the weight of the beam itself if the question says the beam is uniform or gives its mass. Remember weight = mass × gravitational field strength, so 200 g becomes 0.2 kg becomes about 2 N.
  2. Mark the pivot clearly. It is usually a knife edge, a fulcrum, a hinge or the point of support.
  3. Write down perpendicular distances in metres. Distances on a metre rule are given in centimetres, so convert. Always measure from the pivot, not from the end of the rule.
  4. Set up the equation. Sum of anticlockwise moments = sum of clockwise moments. Write it out in symbols and numbers before you touch the calculator.
  5. Solve, then state the unit and check plausibility. A 30 cm answer on a 100 cm rule is sensible. A 130 cm answer means you made a sign or distance error.

Worked example 1: Where to hang the mass

A uniform metre rule is pivoted at the 50 cm mark. A 0.50 N weight hangs at the 20 cm mark. Where must a 1.0 N weight be hung so that the rule balances?

Because the rule is uniform and pivoted at its centre of gravity, its own weight acts through the pivot and produces zero moment. Say that in your working, because it shows understanding.

Anticlockwise moment = 0.50 × (0.50 − 0.20) = 0.50 × 0.30 = 0.15 N m

Clockwise moment = 1.0 × d

For equilibrium: 1.0 × d = 0.15, so d = 0.15 m from the pivot.

The weight is hung at the 65 cm mark.

Worked example 2: Finding the weight of the rule

A uniform metre rule is pivoted at the 30 cm mark. A 0.60 N weight hung at the 10 cm mark keeps it horizontal. Find the weight of the rule.

Here the rule's weight acts at the 50 cm mark, which is 0.20 m from the pivot on the clockwise side.

Anticlockwise: 0.60 × 0.20 = 0.12 N m

Clockwise: W × 0.20

So W × 0.20 = 0.12, giving W = 0.60 N.

The key insight is that a uniform beam behaves as if all its weight is concentrated at its centre of gravity. Examiners love testing this.

Mistakes that cost marks

Explanation questions: the phrasing that scores

If asked why a longer spanner makes it easier to loosen a nut: "A longer spanner gives a larger perpendicular distance from the pivot, so for the same force the moment is larger, and the nut turns more easily."

If asked why a bus with passengers on the lower deck is more stable: "The centre of gravity is lower, so the bus can tilt through a larger angle before its centre of gravity falls outside its base, making it less likely to topple."

Notice the structure: cause, then physics quantity, then consequence. Practise writing in that order and your marks become much more reliable.

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